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Chapter IV: Fundamental Equations of Surface Theory, Congruence Theorem

In curve theory, the fundamental invariants are the curvature and torsion, and the fundamental equations are the Frenet formulas. These express the derivatives of the vectors T, N, and B of the Frenet frames of a curve in terms of these vectors T, N, and B themselves, with the coefficients essentially being the curvature and torsion.
The situation in surface theory is more complicated, but conceptually no different. The fundamental invariants are now the coefficients of the first and second fundamental forms, namely the six functions gij and hij of the parameters (u1,u2). These functions are not independent, and the relationship between them is contained in the theorems of Gauss and Codazzi, to be established in section 3 of this chapter. Taking the place of the Frenet frame is the frame X1,X2,, where X1 and X2 are not orthogonal unit vectors in general. The counterpart of the Frenet equations are the Weingarten and Gauss equations, expressing the partial derivatives of X1,X2, in terms of the vectors X1,X2, themselves.

1. Weingarten and Gauss Equations

Since any vector in E can be written as a linear combination of the three linearly independent vectors X1,X2,, we may write
i = AijXj + Bi.
To determine the coefficients Aij and Bi, we take the dot product with , and the fact that · = 1 immediately leads to ·i = 0 so Bi = 0. Taking the dot product of i with Xj leads to the expression
and we may then solve for the coefficients Aij. To do so, we introduce the inverse matrix (gij) to the matrix (gij), so
gijgjk = dik.
We then get -hikgkm = Aijgjkgkm= Aijdjm = Aim. Thus in the original expression, we have Aij = -hikgkj, which we now denote by -hij. The Weingarten equations for the surface are then
i = -hijXj.
From the Weingarten equations, we immediately derive the theorem, proved earlier: A surface consisting entirely of planar points is a plane. This follows since the hypothesis implies that hij = 0 for all i, j, so i = 0 = j and is constant. This gives Xi· =(X·)i = 0 and (X·)j = 0 so X· = c, a constant, the condition for the surface X to lie in a plane.
More subtle is another consequence of the Weingarten equations:
Proposition 1: A surface with Gaussian curvature K = 0 is, in the neighborhood of a non-planar point, generated by a family of lines such that the tangent plane remains the same along any generator.
Proof: By hypothesis, we have h11h22 - (h12)2 = 0 where h11 and h22 are not both zero. Suppose h 0. Then the equation of the asymptotic curves is
h11(du1)2 + 2h12 du1du2 + h22(du2)2 = 0 = (h11du1 + h22du2)2
du1 = (h22/h11) du2.
We can now make a change of parameters from (u1, u2) to (u1, u2) so that the parametric curve u1 = constant are asymptotic. Then h22=0 and h12 = 0 as well so 2 = 0 and = (u1) is a function of u1 alone. This implies that the normal vectors remain parallel to one another along an asymptotic curve.
Also, we have (X·)2 = X2· + X·2 = 0, so X· = p(u1) is a function depending only on u1. Differentiating with respect to u1 gives X·1 = p'(u1). Note that 1 = -h1jXj = -h1kgkjXj 0 since h11 0 g11. Therefore the asymptotic curve lies in this plane X·1 = p'(u1). But it already lies in the plane X · = c and the vectors and 1 are distinct, so it follows that the asymptotic curve lies in the intersection of two distinct plane, and therefore that it is a straight line. As remarked earlier, the normal vector is constant along this line, so the theorem is proved.
A surface with K = 0 and no planar points is called developable. The reason for this is that any such surface is isometric to a portion of the plane. We may approach this fact in a different way by concentrating on ruled surfaces and singling out those for which the Gaussian curvature is everywhere 0. A ruled surface is of the form X(u1,u2) = Y(u1) + u2Z(u1) for a regular curve Y(u1) and a unit vector field Z(u1) . Then X1(u1,u2) = Y'(u1) + u2Z'(u1) while X2(u1,u2) = Z(u1). Thus X1(u1,u2) x X2(u1,u2) = Y'(u1) x Z(u1) + u2Z'(u1) x Z(u1). When we normalize this vector, the result will be independent of u2 only when Y'(u1) x Z(u1) = 0 identically, i.e. the vector Z(u1) is a multiple of the tangent vector Y'(u1) so we may assume Z(u1) = T(u1), the unit tangent. Thus the ruled surface is the tangential surface of the curve Y(u1) and we have already seen that the metric coefficients of that surface depend only on the curvature of the curve, not on its torsion. There is therefor a curve in the plane with the same curvature and torsion zero, and the tangential surface of this curve, a portion of the plane, will be isometric to the original surface.
The Gauss equations express the second partial derivatives Xikin terms of the vectors X1, X2, and . Let
Xik = ijkXj + cik
where ijk = kji, cik =cki. Taking the dot product with gives cik = Xik· = hik by the definition of the second fundamental form. To determine the coefficients ijk, we take the dot product with Xm to obtain Xik·Xm = ijkXj·Xm = ijkgjm. We set imk = ijkgjm(being careful about the order of the subscripts). Note that imk= kmi but in general there is no symmetry in the other subscripts.
Using the inverse of the first fundamental form, we may write ijk = imkgjm. This process is called "raising or lowering the indices" and the sets of coefficients ijk and imk (or hij and hij) are called "associated"; one set completely determines the other.
We then have Xik·Xm = imk. It follows that
gim/uk = (/uk)Xi·Xm = Xik·Xm + Xi·Xmk = imk + mik,
and similarly
gmk/ui = mki + kmi,
gki/um = kim + ikm.
Adding these last two equations and subtracting the first, we obtain:
ikm = (1/2) ( gmk/ui + gki/um - gim/uk).
It follows that the coefficients ikm, and hence also the ijk, can be expressed completely in terms of the coefficients gik of the first fundamental form and their partial derivatives. The coefficients ikm and ijk are called the Christoffel symbols of the first and second type. It is remarkable that they are intrinsic, depending only on the first fundamental form of the surface.
In summary, the Gauss equations of the surface are
Xik = ijkXj + hik.

Exercises

    When Gauss originally introduced the first and second fundamental forms, he did not use multi-indexed quantities, rather writing I = Edu2 + 2F du dv + Gdv2 and II = Ldu2 + 2M du dv + Ndv2.
  1. Show that H = (1/2)(EN-2FM+GL)/(EG-F2) and K= (LN-M2)/(EG-F2).
  1. Suppose that the lines of curvature are parametric curves, so F = 0 = M. Show that the Weingarten equations become u = -LXu/E and v = -NXv/G, and use these to prove the identity KI - 2H II + III = 0 relating the three fundamental forms.
  1. Use the result of the previous problem to prove that for an asymptotic curve, we have w2 = -K, where w denotes the torsion of the curve (a theorem of Beltrami and Enneper).
  1. If the parametric curves are orthogonal, so F = 0, show that
  2. 111 = (1/2) Eu/E, 121 = -(1/2) Ev/G,
    112 = (1/2) Ev/E, 122 = (1/2) Gu/G,
    212 = -(1/2) Gu/E, 222 = (1/2) Gv/G.
  1. Determine the Christoffel symbols corresponding to polar coordinates in the plane.
  1. Prove that iik = /uk (log g) where g = g11g22 - (g12)2.

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