Proof:IfA = a1Xu(u0,v0) + a2Xv(u0,v0) = b1Xp(p0,q0) + b2Xq(p0,q0) Then
L(A) = a1Nu(u0,v0) +
a2Nv(u0,v0)
= b1Np(p0,q0) +
b2Nq(p0,q0)
Xp(p0,q0) = Xu(u0,v0)(u/p) + Xv(u0,v0)(v/p) and
Np(p0,q0) = Nu(u0,v0)(u/p) + Nv(u0,v0)(v/p) and b1Xp(p0,q0) + b2Xq(p0,q0) = (b1(u/p) + b2(u/q)Xu(u0,v0) + (b1(v/p) + b2(v/q)Xv(u0,v0) So,
a1 = b1(u/p) + b2(u/q) and |