Linear Functions 2D  3D  Tutorial  Contents

Calculus is the study of functions.

Examples

Zero Functions

Constant Functions

Linear Functions

Demos

Figure1

[D]
When we describe a line as the graph of a linear function f(x) = px + k, we are giving a special role to the origin.  Often it is more convenient to consider lines through a particular point (x0,y0) in the plane, and we can describe such a line with slope p by the condition (y-y0)/(x-x0) = p, so y-y0 = p(x-x0).  Choosing different values of the slope p, we obtain all straight lines through (x0,y0) except for the vertical line x = x0

figure1-1-1-a


[D]

figure1-1-1b


[D]


Exercises

  • 1. Find the segment joining the x- and y-intercepts for y = px + k. Describe the segment.
  • 2. Show that if p ≠ 0, then for every y there is a point x such that L(x) = px + k = y



  • Domain, Range & Function Graphs  2D  3D  Parametric Equations  Top of Page  Contents

    One-Variable Calculus considers functions of one real variable.

    The domain of a function of one variable is a subset of the real line { x | x ∈ {R} }.

    The range of a real-valued function f is the collection of all real numbers f(x) where x is in the domain of f.

    The graph of a function of one variable is the collection of points (x,f(x)) in the coordinate plane where x is in the domain of f.

    Demos

    Figure2

    [D]

    Exercises

  • 1. What is the range of the function f(x) = ax2? (The answer will depend on the constant a.)
  • 2. What is the range of the function f(x) = -x4 + 2x2?


  • Slices 2D  3D  Top of Page  Contents

    For every point x0 in the domain of a function f, the intersection of the graph of f with the vertical line x = x0 will be the single point (x0,f(x0)).

    Figure4

    [D]

    Exercises

  • What would happen if we sliced a function graph in the plane with a line that wasn't vertical? Would the slice still always be a single point? Give a proof or a counterexample.


  • Level Sets & Contours 2D   3D  Parametric Equations   Top of Page  Contents

    The collection of all points x in the domain of a function f for which f(x) = k is called the level set of f at level k.

    The set of points (x,f(x)) in the graph such that f(x) = k is called the contour of f at height k.

    Figure 5

    [D]

    A Domain Color Graph in 1D 2D  3D  Top of Page  Contents
    Figure11

    [D]



    Exercises

  • 1. Find the points in the level set for each of the following:
    • f(x) = x, k = 0
    • f(x) = x2 - 1, k = 0
    • f(x) = sin(x), k = √2/2
    • f(x) = tan(x), k = 1
  • 2. Given a function f(x) with level set A at k = 0 and a function g(x) with level set B at k = 0, what is the level set of the function fg(x) (equal to f(x) * g(x)) at k = 0?


  • Continuity
    2D  3D  Parametric Equations  Top of Page  Contents

    One of the most important properties of functions of one real variable is continuity.  

    The basic intuition for continuity is that the range of a function f(x) will lie in an arbitrarily small interval centered at f(x0) if x is restricted to lie in a sufficiently small interval centered at
    x0.  Geometrically, this means that the graph of f(x) will lie between a pair of parallel lines y = f(x0) – ε and y = f(x0) + ε,  i.e. f(x0) – ε < f(x) < f(x0) + ε if x is required to lie in the interval (x0 – δ, x0+ δ), i.e. .  – δ < x-x0 < – δ.

    According to the epsilon-delta definition, a function f of one real variable is said to be continuous at
    x0 if for any ε > 0 there exists a δ such that | f(x) - f(x0) | < ε whenever |x – x0 | < δ.

    A function f of one real variable is said to be continuous if it is continuous at all points
    x0 in its domain.
    Figure7

    [D]

    Exercises

  • 1. Consider the function f(x) = (x - 1)2 for x ≠ 1 and f(1) = 2. Why is this function not continuous at x = 1? What if f(1) = k for some other constant?
  • 2. Consider the function f(x) = tan(x - 1) for x ≠ 1 and f(1) = 2. Why is this function not continuous at x = 1? What if f(1) = k for some other constant?
  • 3. Consider the function f(x) = sin(1/(x-1)) for x ≠ 1 and f(1) = 2. Why is this function not continuous at x = 1? What if f(1) = k for some other constant?